So the second last (ten’s digit) of \({31^{76}}\) is Unit digit of \(3 \times 6 = 18\) or 8. Points: 13662. Can anyone suggest a way I could do this? Any other integer is interpreted as a string containing the decimal digits of the integer. [CAT 2008], Things to note is that the last two digits of. But I want to get as 1914, is it possible? You may have to register or Login before you can post: click the register link above to proceed. So the last two digits of \({78^2} \equiv \) last two digits of \({\left( {100 – 22} \right)^2} \equiv \) last two digits of \({22^2}\) Similarly, the last two digits of \({61^2} \equiv {\left( {50 + 11} \right)^2} \equiv {11^2} \equiv 21\). I was asked by my senior colleague to make a method, which takes two arguments as an input. Help is appreciated. I want to read last two digits of year. Last Two digits: The objective of this article is to understand the concept and approach to solve questions like: There are two-three shortcut approaches to solve the above problems. From the above examples, we can deduce that the if the number is close to 100 or 50, the last two digits of the square of the number is equal to the last two digits of the square of the deviation of the number from the base 100 or 50 (whichever the number if close to). Default is 0: mode: Optional. 05-05-2005, 04:52 PM #2. Rounds number up to precision decimal, when it is half way there. 3. How to extract the last 4 characters from NSString? \({76^{any\;natural\;number}}\) is always 76. The tested string. In this post, Returns the extracted part of a string, or FALSE on failure, or an empty string, A positive number - Start at a specified position in the string, A negative number - Start at a specified position from the end of the string, 0 - Start at the first character in string, A positive number - The length to be returned from the start parameter, Negative number - The length to be returned from the end of the string. Wednesday, February 14, 2018 6:53 PM text/sourcefragment 2/14/2018 7:01:25 PM Bill_Stewart 0 In \({31^{76}}\), the base is 31 (ten’s place is 3) and power is 76 (the unit digit is 6) . polkadot. Also, it crashes if no arguments are provided with subscript out of range (not surprising). text. Once the value of 2^n is calculated, find the last two digits and print it. In the previous post we tried to understand calculating the units digits of large numbers like $2014^{2012}$, $1453^{71}$ etc. Last two digits of year is: 85. Parameters. The inbuilt funtions can also be used to perform this particular task. Method #2 : Using islice() + reversed(). Convert the number by repeatedly squaring until we get the unit digit as 1, and then applying the trick of finding the last two digits of number with unit digit 1 as explained above. Last Two Digits of Large Number. 4. Below is the implementation of the above approach. if no, I think I can get the last two digits of the year, such as 2019, to get … Using the start parameter with different positive and negative numbers: Using the start and length parameters with different positive and negative numbers: If you want to report an error, or if you want to make a suggestion, do not hesitate to send us an e-mail: W3Schools is optimized for learning and training. ljCharlie Register To Reply. How to get last 2 characters from string in C# using Regex? I hope you got all right. If offset is non-negative, the returned string will start at the offset'th position in string, counting from zero.For instance, in the string 'abcdef', the character at position 0 is 'a', the character at position 2 is 'c', and so forth. Specifies the string to return a part of, Required. Note: This approach will only work for 2 n within certain range, as overflow occurs. Any number with its units digit as 0 when raised to any power has 00 as its last two digits. Example: Find the last two digits of \({2^{34}}\), \({2^{34}} \equiv {\left( {{2^{30}}} \right)^4}\), \( \equiv {\left( {{2^{10}}} \right)^3} \times {2^4}\), Example: Find the last two digits of \({62^{48}}\), Observe that \({62^{48}}\) can be written as \({2^{48}} \times {31^{48}}\), Or last two digits of \({62^{48}}\) = last two digits of \({2^{48}}\) \( \times \) last two digits of \({31^{48}}\), Last two digits of \({2^{48}} \equiv {\left( {{2^{10}}} \right)^4} \times {2^8}\), Last two digits of \({31^{48}} \equiv 41\). Hi, Is it possible to insert a formula which can pick just the last 4 digits from a 5 digit number for eg: 25451 I need 5451 / 20192 I need 0192 etc Is it possible to format the cell itself and derive this or is there a formula through which i can derive this on the adjoining cell rgds Number system syllabus and preparation tips for CAT exam. retrieve only month and year (last two digits) part of datetime field. Write a c program to convert octal number to decimal number. If offset is negative, the returned string will start at the offset'th character from the end of string. %let yeartest=2002; %let yeartest2=%sysfunc(putn(&yeartest,year2. Below table shows rules to find last two digits of numbers ending in 5, Example: Find the last two digits of \({135^{123}}\). I did this: Year(1/25/2005) and I get 2005 but I want to list it as 05 instead. Thanks in advance. 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